Trigonometry Vector Problem: Force Angles

Three forces acting at a point are in equilibrium. The forces are 930 lb, 760 lb, and 1220 lb. Find the angles between the directions of the forces. (Hint: Arrange the forces to form the sides of a triangle.)

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Cos A = (b^2+c^2-a^2)/2bc =(930^2+760^2-1220^2)/(2*930*760)= -0.032
Then A=ArcCos(-0.032)=1.6= 92degree
Cos B ...