Physics Rowboat Mercury Weight Density
You (m=80.0 kg) are in a rowboat (m=40.0 kg) of volume 0.300 m3. To answer the following, use the density of seawater as 10,050 N/m3.
Before you step into the rowboat, how much water does the rowboat displace with nothing in it?
What is the maximum load (excluding you and the boat) that you can take on before the rowboat sinks?
If the rowboat was placed in a pool of mercury of weight density Dw = 1.36 X 105 N/m3, how much total weight (in lbs) could you put in the rowboat (including yourself) until it sank?
...but you understand what I mean) due to a displaced volume of water Vdisplaced , FA = water * Vdisplaced , where water = 10050 N/m3 . Since both of them are vertical, but opposite in direction, we can write down that:
Fgrav = FA
mboat * g = water * Vdisplaced
So for the displaced volume we can write that:
Vdisplaced = mboat * g / water = 40 kg 10 m/sec2 /10050 N/m3 3.98 x 10-2 m3
Which is ...