Working with circular motion and centripetal acceleration.

There is a hand held device with a rod with a cord attached to a spring scale on the rod. You swing the ball around in a horizontal circle with a radius of 0.500 m. There are several parts to this that I need help with. If the speed of the ball is 3.7 m/s, how do you calculate the expected tension in the cord? Why can't you swing the ball so the cord remains exactly horizontal? How do you calculate the angle the cord makes?

© SolutionLibrary Inc. 9836dcf9d7

Solution Preview

...toward center = T sin à?.
<br><sum>F=ma horizontally gives: (1) T sin à? = M v^2/R
<br><sum>F vertically = 0 gives: (2) T cos à? = M g
<br>Dividing ...